ATP Tour

Paire v Robredo in Swedish final

2015-07-25 20:09
Benoit Paire (AP)

Bastad - Benoit Paire of France knocked out defending champion Pablo Cuevas of Uruguay 6-4, 6-3 in the Swedish Open semi-finals on Saturday.

Paire will chase his first ATP title on Sunday against Tommy Robredo of Spain, who will be trying for his third Bastad title, following victories in 2006 and 2008.

Robredo defeated German teenager Alexander Zverev 6-3, 6-4 in the other semi-final

Zverev led 2-0 in the second set but couldn't take advantage, missing eight of 10 chances to break Robredo.

Results from the Swedish Open in Bastad on Saturday (x denotes seeded player):


Benot Paire (FRA) bt Pablo Cuevas (URU x3) 6-4, 6-3

Tommy Robredo (ESP x2) bt Alexander Zverev (GER) 6-3, 6-4

Read more on:    atp tour  |  swedish open  |  tommy robredo  |  tennis

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